Flatten a dictionary
Let's suppose is ths our input dictionary.
input: dict = {
"Key1" : "1",
"Key2" : {
"a" : "2",
"b" : "3",
"c" : {
"d" : "3",
"e" : "1"
}
}
}
Then we'd need to produce this output dictionary:
output: {
"Key1" : "1",
"Key2.a" : "2",
"Key2.b" : "3",
"Key2.c.d" : "3",
"Key2.c.e" : "1"
}
Solution
def flatten_dictionary(dictionary):
def flat(outk, ind):
for k, v in ind.items():
if type(v) == dict:
flat("%s.%s"%(outk, k) if outk and k else (outk or k), v)
else:
out[flat_key] = v
out = {}
flat('', dictionary)
return out
Note that a recursive function implements this with the least amount of code. You may be tempted to write a for-loop in the outside function too, however this is not required since we can invoke the inner function with an empty key.
Post by Shyal Beardsley -- to find out more: https://shyal.com, https://ioloop.io